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STE[A]M
Mathematics
Bad Maths
We taught him wrong,
e
i
⋅
P
i
=
−
1
e
i
⋅
P
⋅
i
=
−
1
e
P
⋅
i
⋅
i
=
−
1
e
P
(
i
2
)
=
−
1
e
−
P
=
−
1
e
−
2
P
=
1
P
=
0
→
∴
P
=
N
P
\begin{aligned} &e^{i \cdot Pi}=-1 \\ &e^{i \cdot P \cdot i}=-1 \\ &e^{P \cdot {i \cdot i}}=-1 \\ &e^{P\left(i^{2}\right)}=-1 \\ &e^{-P}=-1 \\&e^{-2 P}=1 \\ &P=0 \rightarrow \boxed{\therefore P=N P} \end{aligned}
e
i
⋅
P
i
=
−
1
e
i
⋅
P
⋅
i
=
−
1
e
P
⋅
i
⋅
i
=
−
1
e
P
(
i
2
)
=
−
1
e
−
P
=
−
1
e
−
2
P
=
1
P
=
0
→
∴
P
=
NP
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Constants
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Calculus
Last updated
2 years ago